📚 Study NotesNDAMathematics · Integral Calculus and Differential Equations📁 Mathematics⏱ ~4 min read🕒 Updated 23 Oct 2026
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Integral Calculus and Differential Equations — Short Notes

⭐ Important points upar highlighted hain — pehle wo padho, phir detail me samjho, aakhir me practice karo.

⭐ Sabse Important Points · एक नज़र में

  • Standard Integrals: Memorize basic forms like ∫x^n dx = x^(n+1)/(n+1) + C (n ≠ -1), ∫1/x dx = ln|x| + C, ∫e^x dx = e^x + C, ∫sin x dx = -cos x + C, etc.
  • Fundamental Theorem: ∫_a^b f(x) dx = F(b) - F(a), where F is an antiderivative of f.
  • Variable Separable: If dy/dx = f(x)g(y), separate as dy/g(y) = f(x)dx and integrate both sides.
  • Integration by Substitution: Use when integrand contains a function and its derivative. Let u = g(x), then du = g'(x)dx.
  • Property of Even/Odd Functions: If f is even, ∫_{-a}^{a} f(x) dx = 2∫_0^a f(x) dx; if f is odd, integral is 0.
  • Homogeneous Equation: If dy/dx = F(y/x), substitute y = vx, then dy/dx = v + x dv/dx, reducing to separable form.

Introduction · परिचय

Integral Calculus and Differential Equations form a key part of NDA Mathematics. This topic covers indefinite and definite integrals, methods of integration, and solving first-order differential equations. Mastery of standard formulas and techniques is essential for scoring well.

Indefinite Integrals and Standard Methods

Indefinite integrals represent the family of antiderivatives of a function. The fundamental methods include substitution, integration by parts, and partial fractions. Recognizing the form of the integrand is crucial for choosing the right method.

📐 Formula / Rule Box · सूत्र याद रखो

Power Rule

∫x^n dx = x^(n+1)/(n+1) + C, n ≠ -1

Integration by Parts

∫u dv = uv - ∫v du

LIATE Rule

Priority for u: Log, Inverse trig, Algebraic, Trig, Exponential

⭐ Key Points · याद रखने वाली बातें

  • Standard Integrals: Memorize basic forms like ∫x^n dx = x^(n+1)/(n+1) + C (n ≠ -1), ∫1/x dx = ln|x| + C, ∫e^x dx = e^x + C, ∫sin x dx = -cos x + C, etc.
  • Integration by Substitution: Use when integrand contains a function and its derivative. Let u = g(x), then du = g'(x)dx.
  • Integration by Parts: ∫u dv = uv - ∫v du. Choose u by LIATE rule (Logarithmic, Inverse trig, Algebraic, Trigonometric, Exponential).
  • Partial Fractions: For rational functions, decompose into simpler fractions before integrating.

✍️ Solved Example 1 · हल किया हुआ उदाहरण

❓ Question: Evaluate ∫x e^x dx

✅ Solution: x e^x - e^x + C

💡 Explanation: Use integration by parts: let u = x, dv = e^x dx. Then du = dx, v = e^x. ∫x e^x dx = x e^x - ∫e^x dx = x e^x - e^x + C.

Definite Integrals and Properties

Definite integrals compute the net area under a curve between limits. Key properties simplify evaluation, especially for even/odd functions and periodic functions.

📐 Formula / Rule Box · सूत्र याद रखो

Fundamental Theorem

∫_a^b f(x) dx = F(b) - F(a)

Even Function

∫_{-a}^{a} f(x) dx = 2∫_0^a f(x) dx

Odd Function

∫_{-a}^{a} f(x) dx = 0

Fundamental Theorem

∫_a^b f(x) dx = F(b) - F(a), where F is an antiderivative of f.

⭐ Key Points · याद रखने वाली बातें

  • Property of Even/Odd Functions: If f is even, ∫_{-a}^{a} f(x) dx = 2∫_0^a f(x) dx; if f is odd, integral is 0.
  • King's Property: ∫_a^b f(x) dx = ∫_a^b f(a+b-x) dx. Useful for trigonometric integrals.
  • Area Interpretation: Definite integral gives signed area; for area between curves, use ∫|f(x)-g(x)| dx.

✍️ Solved Example 1 · हल किया हुआ उदाहरण

❓ Question: Evaluate ∫_{-π/2}^{π/2} sin^3 x dx

✅ Solution: 0

💡 Explanation: sin^3 x is an odd function because sin(-x) = -sin x, so sin^3(-x) = -sin^3 x. Integral over symmetric limits is 0.

First-Order Differential Equations

First-order differential equations involve derivatives of the first order. The main types are variable separable, homogeneous, and linear equations. Solving them requires identifying the type and applying the standard method.

📐 Formula / Rule Box · सूत्र याद रखो

Linear DE Solution

y·e^{∫P dx} = ∫Q·e^{∫P dx} dx + C

Integrating Factor

IF = e^{∫P dx}

Homogeneous Equation

If dy/dx = F(y/x), substitute y = vx, then dy/dx = v + x dv/dx, reducing to separable form.

Linear Differential Equation

Standard form dy/dx + P(x)y = Q(x). Integrating factor (IF) = e^{∫P dx}. Solution: y·IF = ∫Q·IF dx + C.

Exact Equation

If M dx + N dy = 0 and ∂M/∂y = ∂N/∂x, solution is ∫M dx + ∫(terms of N free from x) dy = C.

⭐ Key Points · याद रखने वाली बातें

  • Variable Separable: If dy/dx = f(x)g(y), separate as dy/g(y) = f(x)dx and integrate both sides.

✍️ Solved Example 1 · हल किया हुआ उदाहरण

❓ Question: Solve dy/dx = x/y

✅ Solution: y^2 = x^2 + C

💡 Explanation: Separate variables: y dy = x dx. Integrate: y^2/2 = x^2/2 + C1, so y^2 = x^2 + C (where C = 2C1).

Practice Questions · खुद हल करके देखो

पहले खुद try karo, phir “Answer dekho” dabakar check karo. 👇

Q1Evaluate ∫ (2x + 3)^5 dx

👀 Answer dekho

✅ Answer: (2x + 3)^6 / 12 + C

💡 Explanation: Let u = 2x + 3, then du = 2 dx, so dx = du/2. Integral becomes (1/2)∫u^5 du = (1/2)(u^6/6) + C = u^6/12 + C = (2x+3)^6/12 + C.

Q2Find the integrating factor of dy/dx + (2/x)y = x^2.

👀 Answer dekho

✅ Answer: x^2

💡 Explanation: P(x) = 2/x. IF = e^{∫(2/x) dx} = e^{2 ln x} = e^{ln x^2} = x^2.

Q3Evaluate ∫_0^π sin x dx.

👀 Answer dekho

✅ Answer: 2

💡 Explanation: ∫ sin x dx = -cos x. Evaluate from 0 to π: (-cos π) - (-cos 0) = (-(-1)) - (-1) = 1 + 1 = 2.

⚠️ Common Mistakes · ये गलतियाँ बिल्कुल मत करना

  • Forgetting the constant of integration C in indefinite integrals. Always add C.
  • Misapplying the LIATE rule for integration by parts; choose u according to LIATE to simplify the integral.
  • In definite integrals, ignoring symmetry properties that can simplify the problem; check if the integrand is even or odd.
  • In differential equations, not converting to standard linear form before finding the integrating factor; ensure the coefficient of dy/dx is 1.

⚡ Quick Revision · Exam से पहले 2 मिनट में दोहराओ

  • Standard Integrals: Memorize basic forms like ∫x^n dx, ∫1/x dx, ∫e^x dx, ∫sin x dx, ∫cos x dx, etc.
  • Integration by Parts: Formula ∫u dv = uv - ∫v du; choose u by LIATE.
  • Definite Integral Properties: Use even/odd symmetry and King's property to simplify integrals.
  • Linear Differential Equation: Standard form dy/dx + P(x)y = Q(x); IF = e^{∫P dx}; solution y·IF = ∫Q·IF dx + C.
  • Variable Separable: Separate variables and integrate both sides; don't forget constant C.

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